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3x+(8x*5x)=1015
We move all terms to the left:
3x+(8x*5x)-(1015)=0
We add all the numbers together, and all the variables
3x+(+8x*5x)-1015=0
We get rid of parentheses
3x+8x*5x-1015=0
Wy multiply elements
40x^2+3x-1015=0
a = 40; b = 3; c = -1015;
Δ = b2-4ac
Δ = 32-4·40·(-1015)
Δ = 162409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{162409}=403$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-403}{2*40}=\frac{-406}{80} =-5+3/40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+403}{2*40}=\frac{400}{80} =5 $
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