3x+(x+40)+(4x-20)=180

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Solution for 3x+(x+40)+(4x-20)=180 equation: 



3x+(x+40)+(4x-20)=180

We move all terms to the left:

3x+(x+40)+(4x-20)-(180)=0

We get rid of parentheses

3x+x+4x+40-20-180=0

We add all the numbers together, and all the variables

8x-160=0

We move all terms containing x to the left, all other terms to the right

8x=160

x=160/8

x=20

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