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3x+(x-12)=60
We move all terms to the left:
3x+(x-12)-(60)=0
We get rid of parentheses
3x+x-12-60=0
We add all the numbers together, and all the variables
4x-72=0
We move all terms containing x to the left, all other terms to the right
4x=72
x=72/4
x=18
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