3x+(x-4)2=17

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Solution for 3x+(x-4)2=17 equation: 



3x+(x-4)2=17

We move all terms to the left:

3x+(x-4)2-(17)=0

We multiply parentheses

3x+2x-8-17=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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