3x+(x/2)+1=10-x

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Solution for 3x+(x/2)+1=10-x equation: 



3x+(x/2)+1=10-x

We move all terms to the left:

3x+(x/2)+1-(10-x)=0

We add all the numbers together, and all the variables

3x+(+x/2)-(-1x+10)+1=0

We get rid of parentheses

3x+x/2+1x-10+1=0

We multiply all the terms by the denominator


3x*2+x+1x*2-10*2+1*2=0

We add all the numbers together, and all the variables

x+3x*2+1x*2-18=0

Wy multiply elements

x+6x+2x-18=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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