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3x+(x/2)=56
We move all terms to the left:
3x+(x/2)-(56)=0
We add all the numbers together, and all the variables
3x+(+x/2)-56=0
We get rid of parentheses
3x+x/2-56=0
We multiply all the terms by the denominator
3x*2+x-56*2=0
We add all the numbers together, and all the variables
x+3x*2-112=0
Wy multiply elements
x+6x-112=0
We add all the numbers together, and all the variables
7x-112=0
We move all terms containing x to the left, all other terms to the right
7x=112
x=112/7
x=16
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