3x+(x/3)=40

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Solution for 3x+(x/3)=40 equation:



3x+(x/3)=40
We move all terms to the left:
3x+(x/3)-(40)=0
We add all the numbers together, and all the variables
3x+(+x/3)-40=0
We get rid of parentheses
3x+x/3-40=0
We multiply all the terms by the denominator
3x*3+x-40*3=0
We add all the numbers together, and all the variables
x+3x*3-120=0
Wy multiply elements
x+9x-120=0
We add all the numbers together, and all the variables
10x-120=0
We move all terms containing x to the left, all other terms to the right
10x=120
x=120/10
x=12

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