3x+08=4(x+2)-x

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Solution for 3x+08=4(x+2)-x equation: 



3x+08=4(x+2)-x

We move all terms to the left:

3x+08-(4(x+2)-x)=0

We add all the numbers together, and all the variables

3x-(4(x+2)-x)+8=0



We calculate terms in parentheses: -(4(x+2)-x), so:

4(x+2)-x

We add all the numbers together, and all the variables

-1x+4(x+2)

We multiply parentheses

-1x+4x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We get rid of parentheses

3x-3x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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