3x+0=7(x-2)

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Solution for 3x+0=7(x-2) equation: 



3x+0=7(x-2)

We move all terms to the left:

3x+0-(7(x-2))=0

We add all the numbers together, and all the variables

3x-(7(x-2))=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

3x-7x+14=0

We add all the numbers together, and all the variables

-4x+14=0

We move all terms containing x to the left, all other terms to the right

-4x=-14

x=-14/-4

x=3+1/2

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