3x+1+1/2x+4=18

Solution for 3x+1+1/2x+4=18 equation:

3x+1+1/2x+4=18

We move all terms to the left:

3x+1+1/2x+4-(18)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

3x+1/2x-13=0

We multiply all the terms by the denominator


3x*2x-13*2x+1=0

Wy multiply elements

6x^2-26x+1=0

a = 6; b = -26; c = +1;
Δ = b2-4ac
Δ = -262-4·6·1
Δ = 652
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{652}=\sqrt{4*163}=\sqrt{4}*\sqrt{163}=2\sqrt{163}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{163}}{2*6}=\frac{26-2\sqrt{163}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{163}}{2*6}=\frac{26+2\sqrt{163}}{12}
$