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3x+1+4x+5=(2x-3)
We move all terms to the left:
3x+1+4x+5-((2x-3))=0
We add all the numbers together, and all the variables
7x-((2x-3))+6=0
We calculate terms in parentheses: -((2x-3)), so:We get rid of parentheses
(2x-3)
We get rid of parentheses
2x-3
Back to the equation:
-(2x-3)
7x-2x+3+6=0
We add all the numbers together, and all the variables
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5
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