3x+1/12=5(x-1)/6-2

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Solution for 3x+1/12=5(x-1)/6-2 equation:



3x+1/12=5(x-1)/6-2
We move all terms to the left:
3x+1/12-(5(x-1)/6-2)=0
We calculate fractions
3x+(-(5(x-1)*12)/()+()/()=0
We calculate terms in parentheses: +(-(5(x-1)*12)/()+()/(), so:
-(5(x-1)*12)/()+()/(
We add all the numbers together, and all the variables
-(5(x-1)*12)/()+1
We multiply all the terms by the denominator
-(5(x-1)*12)+1*()
We calculate terms in parentheses: -(5(x-1)*12), so:
5(x-1)*12
We multiply parentheses
60x-60
Back to the equation:
-(60x-60)
We add all the numbers together, and all the variables
-(60x-60)
We get rid of parentheses
-60x+60
Back to the equation:
+(-60x+60)
We get rid of parentheses
3x-60x+60=0
We add all the numbers together, and all the variables
-57x+60=0
We move all terms containing x to the left, all other terms to the right
-57x=-60
x=-60/-57
x=1+1/19

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