3x+1/2(3x-17)=x+(3x-17)+20

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Solution for 3x+1/2(3x-17)=x+(3x-17)+20 equation: 



3x+1/2(3x-17)=x+(3x-17)+20

We move all terms to the left:

3x+1/2(3x-17)-(x+(3x-17)+20)=0



Domain of the equation: 2(3x-17)!=0

x∈R



We multiply all the terms by the denominator


3x*2(3x-17)-((x+(3x-17)+20))*2(3x-17)+1=0



We calculate terms in parentheses: -((x+(3x-17)+20))*2(3x-17), so:

(x+(3x-17)+20))*2(3x-17



Wy multiply elements

6x^2(3-((x+(3x-17)+20))*2(3x-17)+1=0

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