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3x+1/2x+x=110
We move all terms to the left:
3x+1/2x+x-(110)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
4x+1/2x-110=0
We multiply all the terms by the denominator
4x*2x-110*2x+1=0
Wy multiply elements
8x^2-220x+1=0
a = 8; b = -220; c = +1;
Δ = b2-4ac
Δ = -2202-4·8·1
Δ = 48368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48368}=\sqrt{16*3023}=\sqrt{16}*\sqrt{3023}=4\sqrt{3023}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-4\sqrt{3023}}{2*8}=\frac{220-4\sqrt{3023}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+4\sqrt{3023}}{2*8}=\frac{220+4\sqrt{3023}}{16} $
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