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3x+1/2x=22
We move all terms to the left:
3x+1/2x-(22)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
3x*2x-22*2x+1=0
Wy multiply elements
6x^2-44x+1=0
a = 6; b = -44; c = +1;
Δ = b2-4ac
Δ = -442-4·6·1
Δ = 1912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1912}=\sqrt{4*478}=\sqrt{4}*\sqrt{478}=2\sqrt{478}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{478}}{2*6}=\frac{44-2\sqrt{478}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{478}}{2*6}=\frac{44+2\sqrt{478}}{12} $
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