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3x+1/4x+7=-1/4x
We move all terms to the left:
3x+1/4x+7-(-1/4x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 4x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
3x+1/4x+1/4x+7=0
We multiply all the terms by the denominator
3x*4x+7*4x+1+1=0
We add all the numbers together, and all the variables
3x*4x+7*4x+2=0
Wy multiply elements
12x^2+28x+2=0
a = 12; b = 28; c = +2;
Δ = b2-4ac
Δ = 282-4·12·2
Δ = 688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{688}=\sqrt{16*43}=\sqrt{16}*\sqrt{43}=4\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{43}}{2*12}=\frac{-28-4\sqrt{43}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{43}}{2*12}=\frac{-28+4\sqrt{43}}{24} $
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