3x+1/4x=4

Solution for 3x+1/4x=4 equation:

3x+1/4x=4

We move all terms to the left:

3x+1/4x-(4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


3x*4x-4*4x+1=0

Wy multiply elements

12x^2-16x+1=0

a = 12; b = -16; c = +1;
Δ = b2-4ac
Δ = -162-4·12·1
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{13}}{2*12}=\frac{16-4\sqrt{13}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{13}}{2*12}=\frac{16+4\sqrt{13}}{24}
$