3x+1/5=2(x-1)/3-9

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Solution for 3x+1/5=2(x-1)/3-9 equation:



3x+1/5=2(x-1)/3-9
We move all terms to the left:
3x+1/5-(2(x-1)/3-9)=0
We calculate fractions
3x+(-(2(x-1)*5)/()+()/()=0
We calculate terms in parentheses: +(-(2(x-1)*5)/()+()/(), so:
-(2(x-1)*5)/()+()/(
We add all the numbers together, and all the variables
-(2(x-1)*5)/()+1
We multiply all the terms by the denominator
-(2(x-1)*5)+1*()
We calculate terms in parentheses: -(2(x-1)*5), so:
2(x-1)*5
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
We add all the numbers together, and all the variables
-(10x-10)
We get rid of parentheses
-10x+10
Back to the equation:
+(-10x+10)
We get rid of parentheses
3x-10x+10=0
We add all the numbers together, and all the variables
-7x+10=0
We move all terms containing x to the left, all other terms to the right
-7x=-10
x=-10/-7
x=1+3/7

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