3x+1/5=2(x-1)/3=9

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Solution for 3x+1/5=2(x-1)/3=9 equation: 



3x+1/5=2(x-1)/3=9

We move all terms to the left:

3x+1/5-(2(x-1)/3)=0

We calculate fractions


3x+(-(2(x-1)*5)/()+()/()=0



We calculate terms in parentheses: +(-(2(x-1)*5)/()+()/(), so:

-(2(x-1)*5)/()+()/(

We add all the numbers together, and all the variables

-(2(x-1)*5)/()+1

We multiply all the terms by the denominator


-(2(x-1)*5)+1*()



We calculate terms in parentheses: -(2(x-1)*5), so:

2(x-1)*5

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

-(10x-10)

We get rid of parentheses

-10x+10

Back to the equation:

+(-10x+10)



We get rid of parentheses

3x-10x+10=0

We add all the numbers together, and all the variables

-7x+10=0

We move all terms containing x to the left, all other terms to the right

-7x=-10

x=-10/-7

x=1+3/7

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