3x+1/x-5=7

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Solution for 3x+1/x-5=7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+1/x-5 = 7 // - 7

3*x+1/x-7-5 = 0

3*x^1+1*x^-1-12*x^0 = 0

(3*x^2-12*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-12*x^1+1*x^0) = 0

x^1

3*x^2-12*x+1 = 0

3*x^2-12*x+1 = 0

DELTA = (-12)^2-(1*3*4)

DELTA = 132

DELTA > 0

x = (132^(1/2)+12)/(2*3) or x = (12-132^(1/2))/(2*3)

x = (2*33^(1/2)+12)/6 or x = (12-2*33^(1/2))/6

x in { (12-2*33^(1/2))/6, (2*33^(1/2)+12)/6} 

x in { (12-2*33^(1/2))/6, (2*33^(1/2)+12)/6 }

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