3x+10+(x+1)+(2x+2)+12=61

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Solution for 3x+10+(x+1)+(2x+2)+12=61 equation:


Simplifying
3x + 10 + (x + 1) + (2x + 2) + 12 = 61

Reorder the terms:
3x + 10 + (1 + x) + (2x + 2) + 12 = 61

Remove parenthesis around (1 + x)
3x + 10 + 1 + x + (2x + 2) + 12 = 61

Reorder the terms:
3x + 10 + 1 + x + (2 + 2x) + 12 = 61

Remove parenthesis around (2 + 2x)
3x + 10 + 1 + x + 2 + 2x + 12 = 61

Reorder the terms:
10 + 1 + 2 + 12 + 3x + x + 2x = 61

Combine like terms: 10 + 1 = 11
11 + 2 + 12 + 3x + x + 2x = 61

Combine like terms: 11 + 2 = 13
13 + 12 + 3x + x + 2x = 61

Combine like terms: 13 + 12 = 25
25 + 3x + x + 2x = 61

Combine like terms: 3x + x = 4x
25 + 4x + 2x = 61

Combine like terms: 4x + 2x = 6x
25 + 6x = 61

Solving
25 + 6x = 61

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + 6x = 61 + -25

Combine like terms: 25 + -25 = 0
0 + 6x = 61 + -25
6x = 61 + -25

Combine like terms: 61 + -25 = 36
6x = 36

Divide each side by '6'.
x = 6

Simplifying
x = 6

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