3x+10+2x=2x(x+8)

Solution for 3x+10+2x=2x(x+8) equation:

3x+10+2x=2x(x+8)

We move all terms to the left:

3x+10+2x-(2x(x+8))=0

We add all the numbers together, and all the variables

5x-(2x(x+8))+10=0


We calculate terms in parentheses: -(2x(x+8)), so:

2x(x+8)

We multiply parentheses

2x^2+16x

Back to the equation:

-(2x^2+16x)


We get rid of parentheses

-2x^2+5x-16x+10=0

We add all the numbers together, and all the variables

-2x^2-11x+10=0

a = -2; b = -11; c = +10;
Δ = b2-4ac
Δ = -112-4·(-2)·10
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{201}}{2*-2}=\frac{11-\sqrt{201}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{201}}{2*-2}=\frac{11+\sqrt{201}}{-4}
$