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3x+10=2x(4+3x)+64
We move all terms to the left:
3x+10-(2x(4+3x)+64)=0
We add all the numbers together, and all the variables
3x-(2x(3x+4)+64)+10=0
We calculate terms in parentheses: -(2x(3x+4)+64), so:We get rid of parentheses
2x(3x+4)+64
We multiply parentheses
6x^2+8x+64
Back to the equation:
-(6x^2+8x+64)
-6x^2+3x-8x-64+10=0
We add all the numbers together, and all the variables
-6x^2-5x-54=0
a = -6; b = -5; c = -54;
Δ = b2-4ac
Δ = -52-4·(-6)·(-54)
Δ = -1271
Delta is less than zero, so there is no solution for the equation
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