3x+10x-2=128

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Solution for 3x+10x-2=128 equation: 



3x+10x-2=128

We move all terms to the left:

3x+10x-2-(128)=0

We add all the numbers together, and all the variables

13x-130=0

We move all terms containing x to the left, all other terms to the right

13x=130

x=130/13

x=10

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