3x+112+5x+100=80

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Solution for 3x+112+5x+100=80 equation: 



3x+112+5x+100=80

We move all terms to the left:

3x+112+5x+100-(80)=0

We add all the numbers together, and all the variables

8x+132=0

We move all terms containing x to the left, all other terms to the right

8x=-132

x=-132/8

x=-16+1/2

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