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3x+11=9-1/3x
We move all terms to the left:
3x+11-(9-1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(-1/3x+9)+11=0
We get rid of parentheses
3x+1/3x-9+11=0
We multiply all the terms by the denominator
3x*3x-9*3x+11*3x+1=0
Wy multiply elements
9x^2-27x+33x+1=0
We add all the numbers together, and all the variables
9x^2+6x+1=0
a = 9; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·9·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-6}{18}=-1/3$
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