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3x+12(-4x+10)=10-5(10x-4)
We move all terms to the left:
3x+12(-4x+10)-(10-5(10x-4))=0
We multiply parentheses
3x-48x-(10-5(10x-4))+120=0
We calculate terms in parentheses: -(10-5(10x-4)), so:We add all the numbers together, and all the variables
10-5(10x-4)
determiningTheFunctionDomain -5(10x-4)+10
We multiply parentheses
-50x+20+10
We add all the numbers together, and all the variables
-50x+30
Back to the equation:
-(-50x+30)
-45x-(-50x+30)+120=0
We get rid of parentheses
-45x+50x-30+120=0
We add all the numbers together, and all the variables
5x+90=0
We move all terms containing x to the left, all other terms to the right
5x=-90
x=-90/5
x=-18
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