3x+12(-4x+10)=10-5(10x-4)

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Solution for 3x+12(-4x+10)=10-5(10x-4) equation: 



3x+12(-4x+10)=10-5(10x-4)

We move all terms to the left:

3x+12(-4x+10)-(10-5(10x-4))=0

We multiply parentheses

3x-48x-(10-5(10x-4))+120=0



We calculate terms in parentheses: -(10-5(10x-4)), so:

10-5(10x-4)

determiningTheFunctionDomain
-5(10x-4)+10

We multiply parentheses

-50x+20+10

We add all the numbers together, and all the variables

-50x+30

Back to the equation:

-(-50x+30)



We add all the numbers together, and all the variables

-45x-(-50x+30)+120=0

We get rid of parentheses

-45x+50x-30+120=0

We add all the numbers together, and all the variables

5x+90=0

We move all terms containing x to the left, all other terms to the right

5x=-90

x=-90/5

x=-18

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