3x+12+3x-2=40

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Solution for 3x+12+3x-2=40 equation: 



3x+12+3x-2=40

We move all terms to the left:

3x+12+3x-2-(40)=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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