3x+12+6x=3(4+3x)

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Solution for 3x+12+6x=3(4+3x) equation: 



3x+12+6x=3(4+3x)

We move all terms to the left:

3x+12+6x-(3(4+3x))=0

We add all the numbers together, and all the variables

3x+6x-(3(3x+4))+12=0

We add all the numbers together, and all the variables

9x-(3(3x+4))+12=0



We calculate terms in parentheses: -(3(3x+4)), so:

3(3x+4)

We multiply parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

9x-9x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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