3x+12+x2+4x=x

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Solution for 3x+12+x2+4x=x equation: 



3x+12+x2+4x=x

We move all terms to the left:

3x+12+x2+4x-(x)=0

We add all the numbers together, and all the variables

x^2+6x+12=0

a = 1; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·1·12
Δ = -12
Delta is less than zero, so there is no solution for the equation

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