3x+12-4-4x=3x-18+36+6

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Solution for 3x+12-4-4x=3x-18+36+6 equation: 



3x+12-4-4x=3x-18+36+6

We move all terms to the left:

3x+12-4-4x-(3x-18+36+6)=0

We add all the numbers together, and all the variables

3x-4x-(3x+24)+12-4=0

We add all the numbers together, and all the variables

-1x-(3x+24)+8=0

We get rid of parentheses

-1x-3x-24+8=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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