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3x+12-6x=2(4-2x)
We move all terms to the left:
3x+12-6x-(2(4-2x))=0
We add all the numbers together, and all the variables
3x-6x-(2(-2x+4))+12=0
We add all the numbers together, and all the variables
-3x-(2(-2x+4))+12=0
We calculate terms in parentheses: -(2(-2x+4)), so:We get rid of parentheses
2(-2x+4)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
-3x+4x-8+12=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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