3x+129=3(11+7x)

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Solution for 3x+129=3(11+7x) equation: 



3x+129=3(11+7x)

We move all terms to the left:

3x+129-(3(11+7x))=0

We add all the numbers together, and all the variables

3x-(3(7x+11))+129=0



We calculate terms in parentheses: -(3(7x+11)), so:

3(7x+11)

We multiply parentheses

21x+33

Back to the equation:

-(21x+33)



We get rid of parentheses

3x-21x-33+129=0

We add all the numbers together, and all the variables

-18x+96=0

We move all terms containing x to the left, all other terms to the right

-18x=-96

x=-96/-18

x=5+1/3

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