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3x+12=(10)
We move all terms to the left:
3x+12-((10))=0
determiningTheFunctionDomain 3x+12-10=0
We add all the numbers together, and all the variables
3x+2=0
We move all terms containing x to the left, all other terms to the right
3x=-2
x=-2/3
x=-2/3
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