3x+12=(2x-6)/4

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Solution for 3x+12=(2x-6)/4 equation: 



3x+12=(2x-6)/4

We move all terms to the left:

3x+12-((2x-6)/4)=0

We multiply all the terms by the denominator


3x*4)-((2x-6)+12*4)=0

We add all the numbers together, and all the variables

3x*4)-((2x-6)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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