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3x+12=(x+12)
We move all terms to the left:
3x+12-((x+12))=0
We calculate terms in parentheses: -((x+12)), so:We get rid of parentheses
(x+12)
We get rid of parentheses
x+12
Back to the equation:
-(x+12)
3x-x-12+12=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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