3x+12=19x-93

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Solution for 3x+12=19x-93 equation: 



3x+12=19x-93

We move all terms to the left:

3x+12-(19x-93)=0

We get rid of parentheses

3x-19x+93+12=0

We add all the numbers together, and all the variables

-16x+105=0

We move all terms containing x to the left, all other terms to the right

-16x=-105

x=-105/-16

x=6+9/16

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