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3x+12=2(x+3)+4
We move all terms to the left:
3x+12-(2(x+3)+4)=0
We calculate terms in parentheses: -(2(x+3)+4), so:We get rid of parentheses
2(x+3)+4
We multiply parentheses
2x+6+4
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
3x-2x-10+12=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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