3x+12=2(x-2)+2(x+4)

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Solution for 3x+12=2(x-2)+2(x+4) equation: 



3x+12=2(x-2)+2(x+4)

We move all terms to the left:

3x+12-(2(x-2)+2(x+4))=0



We calculate terms in parentheses: -(2(x-2)+2(x+4)), so:

2(x-2)+2(x+4)

We multiply parentheses

2x+2x-4+8

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

3x-4x-4+12=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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