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3x+12=3(x+4)+1
We move all terms to the left:
3x+12-(3(x+4)+1)=0
We calculate terms in parentheses: -(3(x+4)+1), so:We get rid of parentheses
3(x+4)+1
We multiply parentheses
3x+12+1
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
3x-3x-13+12=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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