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3x+12=4x-(2x-5)
We move all terms to the left:
3x+12-(4x-(2x-5))=0
We calculate terms in parentheses: -(4x-(2x-5)), so:We get rid of parentheses
4x-(2x-5)
We get rid of parentheses
4x-2x+5
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
3x-2x-5+12=0
We add all the numbers together, and all the variables
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7
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