3x+12=4x-68

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Solution for 3x+12=4x-68 equation: 



3x+12=4x-68

We move all terms to the left:

3x+12-(4x-68)=0

We get rid of parentheses

3x-4x+68+12=0

We add all the numbers together, and all the variables

-1x+80=0

We move all terms containing x to the left, all other terms to the right

-x=-80

x=-80/-1

x=+80

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