3x+12=5(2x+1)+7(x-1)

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Solution for 3x+12=5(2x+1)+7(x-1) equation: 



3x+12=5(2x+1)+7(x-1)

We move all terms to the left:

3x+12-(5(2x+1)+7(x-1))=0



We calculate terms in parentheses: -(5(2x+1)+7(x-1)), so:

5(2x+1)+7(x-1)

We multiply parentheses

10x+7x+5-7

We add all the numbers together, and all the variables

17x-2

Back to the equation:

-(17x-2)



We get rid of parentheses

3x-17x+2+12=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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