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3x+13-4x(6x+19)=0
We multiply parentheses
-24x^2+3x-76x+13=0
We add all the numbers together, and all the variables
-24x^2-73x+13=0
a = -24; b = -73; c = +13;
Δ = b2-4ac
Δ = -732-4·(-24)·13
Δ = 6577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-\sqrt{6577}}{2*-24}=\frac{73-\sqrt{6577}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+\sqrt{6577}}{2*-24}=\frac{73+\sqrt{6577}}{-48} $
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