3x+13=(4x+9x-16)1/2

Solution for 3x+13=(4x+9x-16)1/2 equation:

3x+13=(4x+9x-16)1/2

We move all terms to the left:

3x+13-((4x+9x-16)1/2)=0

We add all the numbers together, and all the variables

3x-((13x-16)1/2)+13=0

We multiply all the terms by the denominator


3x*2)-((13x-16)1+13*2)=0

We add all the numbers together, and all the variables

3x*2)-((13x-16)1=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$