3x+13=1/2(8x+48-5x-20

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Solution for 3x+13=1/2(8x+48-5x-20 equation: 



3x+13=1/2(8x+48-5x-20

We move all terms to the left:

3x+13-(1/2(8x+48-5x-20)=0



Domain of the equation: 2(8x+48-5x-20)+13!=0

We move all terms containing x to the left, all other terms to the right

2(8x+48-5x-20)!=-13

x∈R



We add all the numbers together, and all the variables

3x-(1/2(3x+28)+13=0

We multiply all the terms by the denominator


3x*2(3x+28)+13-(1=0

We add all the numbers together, and all the variables

3x*2(3x+28)=0

Wy multiply elements

6x^2(3=0

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