3x+13=17(x+2)-4(x+7)

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Solution for 3x+13=17(x+2)-4(x+7) equation: 



3x+13=17(x+2)-4(x+7)

We move all terms to the left:

3x+13-(17(x+2)-4(x+7))=0



We calculate terms in parentheses: -(17(x+2)-4(x+7)), so:

17(x+2)-4(x+7)

We multiply parentheses

17x-4x+34-28

We add all the numbers together, and all the variables

13x+6

Back to the equation:

-(13x+6)



We get rid of parentheses

3x-13x-6+13=0

We add all the numbers together, and all the variables

-10x+7=0

We move all terms containing x to the left, all other terms to the right

-10x=-7

x=-7/-10

x=7/10

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