3x+13=2(x-3)-4(-10+5x)

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Solution for 3x+13=2(x-3)-4(-10+5x) equation: 



3x+13=2(x-3)-4(-10+5x)

We move all terms to the left:

3x+13-(2(x-3)-4(-10+5x))=0

We add all the numbers together, and all the variables

3x-(2(x-3)-4(5x-10))+13=0



We calculate terms in parentheses: -(2(x-3)-4(5x-10)), so:

2(x-3)-4(5x-10)

We multiply parentheses

2x-20x-6+40

We add all the numbers together, and all the variables

-18x+34

Back to the equation:

-(-18x+34)



We get rid of parentheses

3x+18x-34+13=0

We add all the numbers together, and all the variables

21x-21=0

We move all terms containing x to the left, all other terms to the right

21x=21

x=21/21

x=1

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