3x+13=3(x+6)+13x+13=3(x+6)+1

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Solution for 3x+13=3(x+6)+13x+13=3(x+6)+1 equation: 



3x+13=3(x+6)+13x+13=3(x+6)+1

We move all terms to the left:

3x+13-(3(x+6)+13x+13)=0



We calculate terms in parentheses: -(3(x+6)+13x+13), so:

3(x+6)+13x+13

We add all the numbers together, and all the variables

13x+3(x+6)+13

We multiply parentheses

13x+3x+18+13

We add all the numbers together, and all the variables

16x+31

Back to the equation:

-(16x+31)



We get rid of parentheses

3x-16x-31+13=0

We add all the numbers together, and all the variables

-13x-18=0

We move all terms containing x to the left, all other terms to the right

-13x=18

x=18/-13

x=-1+5/13

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