3x+14/(5x)=7

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Solution for 3x+14/(5x)=7 equation:


D( x )

5*x = 0

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:0) U (0:+oo)

3*x+14/(5*x) = 7 // - 7

3*x+14/(5*x)-7 = 0

3*x^1+14/5*x^-1-7*x^0 = 0

(3*x^2-7*x^1+14/5*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-7*x^1+14/5*x^0) = 0

x^1

3*x^2-7*x+14/5 = 0

3*x^2-7*x+14/5 = 0

DELTA = (-7)^2-(3*4*(14/5))

DELTA = 77/5

DELTA > 0

x = ((77/5)^(1/2)+7)/(2*3) or x = (7-(77/5)^(1/2))/(2*3)

x = ((77/5)^(1/2)+7)/6 or x = (7-(77/5)^(1/2))/6

x in { (7-(77/5)^(1/2))/6, ((77/5)^(1/2)+7)/6}

x in { (7-(77/5)^(1/2))/6, ((77/5)^(1/2)+7)/6 }

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